MQL5 How to find lastest history order ticket?

External question — Stack Overflow Stack Exchange Author: Abbotton Original post: https://stackoverflow.com/questions/78447537 License: CC BY-SA 4.0 — https://creativecommons.org/licenses/by-sa/4.0/ Adaptation: HTML converted to plain text; contact email addresses removed. I am writing an EA program using MQL5, and now I encounter a problem. I want to get the order number of the last closed order (as shown below, the target order number is 2308697611 ). I have tried many methods but cannot solve this problem. The last attempt was to use the following code: HistorySelect(0, TimeCurrent()); ulong ticket = HistoryDealGetTicket(HistoryDealsTotal() - 2); But these two lines of code will only take effect if the positions are closed sequentially. If I close the positions randomly, I will not get the expected results.

External answer — Stack Overflow Stack Exchange Author: 4xPip Official Original post: https://stackoverflow.com/a/79261487 License: CC BY-SA 4.0 — https://creativecommons.org/licenses/by-sa/4.0/ Adaptation: HTML converted to plain text; contact email addresses removed. Using the following function, you can get the ticket number of last closed ticket in MQL5. int lastClosedTicket() { HistorySelect(0, TimeCurrent()); uint total_trades = HistoryDealsTotal(); ulong ticket_number = 0; for(int i =(int) total_trades - 1; i >= 0 ; --i) { if((ticket_number = HistoryDealGetTicket(i)) > 0) { return HistoryDealGetInteger(ticket_number, DEAL_TICKET) } } }