Collect Price values High[0] to High[50] mql4

External question — Stack Overflow Stack Exchange Author: Qan N Original post: https://stackoverflow.com/questions/73515729 License: CC BY-SA 4.0 — https://creativecommons.org/licenses/by-sa/4.0/ Adaptation: HTML converted to plain text; contact email addresses removed. I was creating a for loop that looks for mean of price within a set array of 50. the difficulty I am having is with the collection and storage of High[0] to High[50] (Low[0] to Low[50]) data for the mean equation M= (Total Value/nbars) I was trying to follow C++: float arithmeticMean(float [], int); int main() { int n, i; float arr[50], armean; cout<<"Enter the Size (maz. 50): "; cin>>n; cout<<"\nEnter "<<n<<" Numbers: "; for(i=0; i<n; i++) cin>>arr[i]; armean = arithmeticMean(arr, n); cout<<"\nArithmetic Mean = "<<armean; cout<<endl; return 0; } float arithmeticMean(float arr[], int n) { int i; float sum=0, am; for(i=0; i<n; i++) sum = sum+arr[i]; am = sum/n; return am; } And I attempted to resize the buffer and store price values, but this isn't correct, ideas?: { int d = High[50]+Low[50]; double rb[],armean; for(int s=-1; Close[s]<d; Close[s++]) //Array Iteration Loop Forward BarsToCheck { double Meansize = ArrayResize(rb,s); double sum = Meansize+rb[s]; } armean = sum/d; }

External answer — Stack Overflow Stack Exchange Author: PaulB Original post: https://stackoverflow.com/a/73517129 License: CC BY-SA 4.0 — https://creativecommons.org/licenses/by-sa/4.0/ Adaptation: HTML converted to plain text; contact email addresses removed. You are really getting things confused, just keep it simple. Also remember that arrays are 0 based, therefore, if you want to count 50 items you will run from 0 to 49. double total=0.0; int count=50; for(int i=count-1; i>=0; i--) total+=High[i]; double mean=total/count;